Question

How do you multiply `(y ^ { 2} + 4) ( 3y + 9)`?

Answer 1

See a solution process below:

Explanation:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

`(color(red)(y^2) + color(red)(4))(color(blue)(3y) + color(blue)(9))` becomes:

`(color(red)(y^2) xx color(blue)(3y)) + (color(red)(y^2) xx color(blue)(9)) + (color(red)(4) xx color(blue)(3y)) + (color(red)(4) xx color(blue)(9))`

`3y^3 + 9y^2 + 12y + 36`