Why is acceleration inversely proportional to time squared?

2 Answers
Sep 5, 2017

Please refer to explanation

Explanation:

The S.I. unit of acceleration is #ms^(-2)# , but why?
Lets checkout.
we know the S.I. unit of distance is #m#.
and of time is #sec or s#
& velocity is displacement per unit time so unit of velcity become #ms^(-1)#

and acceleration is change is velocity per unit time
#a=(v-u)/t#
representing is S.I. units
S.I unit of acceleration# -> (ms^(-1))/s -> ms^(-2) or m/s^(2)#
[remember change in velocity will also have unit #ms^(-1)#].
hope it helps!!

Jan 29, 2018

See explanation

Explanation:

Its all to do with rate of increase in velocity

Suppose the velocity increased by 2 seconds at every second

Time in seconds#color(white)("ddd") 0,color(white)("d")1,color(white)("d")2,color(white)("d")3,color(white)("dd")4,color(white)("dd")5, ....#
#color(white)("dddddddddddddd")uarr color(white)("d")uarr color(white)("d")uarr color(white)(".")uarr color(white)("d.") uarr color(white)("d.")uarr#
Velocity in #color(white)("ddddddd")0,color(white)("d")2,color(white)("d")4,color(white)("d")6,color(white)("dd")8,color(white)("d")10, ....#
metres per second

Given that #ul("each increase in velocity")# is

#2color(white)(.) ("metres")/("second") larr " 2m per second" -> 2m/s#
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("This is what can go wrong")#

The units of measurement fail #ul("in this approach")# so something is wrong with it:

Set time as represented by #t" seconds"#

Then the velocity at any time time #t# is:

#->2color(white)(.) ("metres")/(cancel("second")) xxtcolor(white)(".") cancel("seconds") = 2t" metres"color(red)(larr" Fail"#

#color(blue)("Making it work")#

We end up with only 'metres' as the unit of measurement. For velocity we must have metres per second #->("metres")/("second")#

To #ul("'FORCE'")# the above to work we must #color(red)("square")# the seconds.

So we use #color(white)(...)2color(white)(.) ("metres")/("second"^(color(red)(2)))color(white)(.)# instead giving:

#color(white)()#

#2color(white)(.) ("metres")/("second"^(color(red)(cancel(color(white)(.)2)))) xxtcolor(white)(".") cancel("seconds") = 2t("metres")/("second") ->2tcolor(white)(.) "m/s"#

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("Foot note")#

Another way of writing #color(white)("..")2 color(white)(.) ("metres")/("second"^(2)) ->2 m/s^2color(white)(.)# is #color(white)(.)2ms^(-2)#