Question

How do you evaluate `\frac { 4\cdot ( x - 1) } { ( 1- x ) \cdot 2}`?

Answer 1

`-2`

Explanation:

`(4 * (x - 1))/((1 - x) *2)`

change a sign for `(x - 1)` to `- (-x + 1) = - (1 - x)`

`(4 * - (1 - x))/((1 - x) * 2) = (-4 *cancel((1 - x)))/(cancel((1 - x)) *2)`

`= -4 /2 = -2`