How do you graph #10x + 11y - 45= 0#?

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Answer 1 · 2017-09-06T19:53:33

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point:

For #x = 0#

#(10 * 0) + 11y - 45 = 0#
#0 + 11y - 45 + color(red)(45) = 0 + color(red)(45)#
#11y - 0 = 45#
#11y = 45#

#(11y)/color(red)(11) = 45/color(red)(11)#

#y = 45/11# or #(0, 45/11)#

Second Point:

For #y = 0#

#10x + (11 * 0) - 45 = 0#
#10x + 0 - 45 + color(red)(45) = 0 + color(red)(45)#
#10x - 0 = 45#
#10x = 45#

#(10x)/color(red)(10) = 45/color(red)(10)#

#x = 45/10# or #(45/10, 0)#

We can next graph the two points on the coordinate plane:

graph{(x^2+(y- 45/11)^2-0.075)((x- 45/10)^2+y^2-0.075)=0 [-20, 20, -10, 10]}

Now, we can draw a straight line through the two points to graph the line:

graph{(10x + 11y - 45)(x^2+(y- 45/11)^2-0.075)((x- 45/10)^2+y^2-0.075)=0 [-20, 20, -10, 10]}