How do you solve the system of linear equations #y= - 2+ 3x# and #y = - 14+ 6x# by substitution?

1 Answer
Sep 8, 2017

#(x,y)=(4,10)#
#color(white)("XXX")#see below for method using substitution

Explanation:

Given
[1]#color(white)("XXX")y=-2+3x#
[2]#color(white)("XXX")y=-14+6x#

From [2] we know we can substitute #-14+6x# for #y# in [1]
[3]#color(white)("XXX")-14+6x=-2+3x#

Adding #14# to both sides:
[4]#color(white)("XXX")6x=12+3x#

then subtracting #3x# from both sides
[5]#color(white)("XXX")3x=12#

and dividing both sides by #3#
[6]#color(white)("XXX")x=4#

From [5] we now know that we can substitute #4# for #x# in [1]
[6]#color(white)("XXX")y=-2+3xx4#

After simplifying
[7]#color(white)("XXX")y=10#

So #(x,y)=(4,10)#