Question #d35e3

1 Answer
Sep 8, 2017

Consider a piece of conductor of cross sectional area #A#.

Now, if #n# be the concentration of charge carriers (electrons or Cooper pairs or electron-holes or whatever it may be). Then, in #dt# time, the number of charge carriers that pass through the cross section is,

#dN = nv_dAdt# where #v_d# is the drift speed.

This holds because #v_d*dt# is length of conductor whose free charges pass through #A# in time #dt# and hence the associated volume is #dV = v_ddt*A# whose charges constitute the current in #dt# time through area #A#.

Then charge passing through the area is,

#dQ = nqv_dAdt# where #q# is charge on each charge carrier.

Therefore the current,

#I = (dQ)/(dt) = nqv_dA#