How do you evaluate #7.3 * 10^11*(7.6*10^11 + 2*7.6*10^11*2(1/(7.6*10^11))+2^((2*7.6*10^11))#?

1 Answer
Robert C.
Sep 8, 2017

a number bigger than anyone could ever possibly use

Explanation:

The end bracket is missing so I presumed it location when i started working on this. One good thing is that you can eliminate the #(2 (7.6 * 10^11))# and the #(2(1/(7.6*10^11))# since they cancel each other out.

As far as the rest of the numbers go you are multiplying #73,000,000,000# by the sum of #76,000,000,000# and #2^(1.52 * 10^12)#. That's a big number.

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