How do you solve #3( x + 9) - 6= x + 19#?

1 Answer
Jim G.
Sep 8, 2017

#x=-1#

Explanation:

#"distribute the bracket on the left of the equation"#

#3x+27-6=x+19#

#rArr3x+21=x+19#

#"collect terms in x on the left and numeric values on the right"#

#"subtract x from both sides"#

#3x-x+21=cancel(x)cancel(-x)+19#

#rArr2x+21=19#

#"subtract 21 from both sides"#

#2xcancel(+21)cancel(-21)=19-21#

#rArr2x=-2#

#"divide both sides by 2"#

#(cancel(2) x)/cancel(2)=(-2)/2#

#rArrx =-1#

#color(blue)"As a check"#

Substitute this value into the equation and if both sides are equal then it is the solution.

#"left "=3(-1+9)-6=-3xx8-6=24-6=18#

#"right "=-1+19=18#

#rArrx=-1" is the solution"#

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