How do you solve #\frac { 4+ b } { 6} = 0#?

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Answer 1 · 2017-09-09T01:19:10

See a solution process below:

First, multiply each side of the equation by #color(red)(6)# to eliminate the fraction while keeping the equation balanced:

#color(red)(6) xx (4 + b)/6 = color(red)(6) xx 0#

#cancel(color(red)(6)) xx (4 + b)/color(red)(cancel(color(black)(6))) = 0#

#4 + b = 0#

Now, subtract #color(red)(4)# from each side of the equation to solve for #b# while keeping the equation balanced:

#-color(red)(4) + 4 + b = -color(red)(4) + 0#

#0 + b = -4#

#b = -4#