Question

Question #f3e56

Answer 1

Turn it into a quadratic equation...

Explanation:

...which I don't think is too tough:

Multiply out the left side:

`x^2 - 2x + 1 = 4x - 5`

Subtract 4x from both sides:

`x^2 - 6x + 1 = -5`

....add 5 to both sides:

`x^2 - 6x + 6 = 0`

So now it's in the classic quadratic equation form ax^2 +bx + c = 0,
where a = 1, b = -6, and c = 6.

And I'll bet you've seen these solved before...

the roots here are given by the familiar formula:

`x = (-b+-sqrt(b^2 - 4ac))/(2a)`

with roots 4.73 and 1.27 (rounded to 3 digits)

GOOD LUCK!