Question #0f718

1 Answer
Sep 9, 2017

see explanation:

Explanation:

First of all, note that your problem is, in fact, in the standard form:

#ax^2 + bx + c = 0#, where a = 3, b = 29, and c = -9.5.

(If it wasn't, you'd have some work to do to get it into that form.)

The quadratic formula is:

#x = (-b+-sqrt(b^2 - 4ac))/(2a)#

...so you plug in your a, b, and c, and get:

x = -9.98 and 0.317 (rounding to 3 digits).

GOOD LUCK!