Question

What volume of ammonia may be prepared from a `1*g` mass of dinitrogen gas?

Answer 1

Approx. `1*L` of ammonia............

Explanation:

We need (i) a stoichiometric equation.....

`1/2N_2(g) + 3/2H_2(g)rightleftharpoonsNH_3(g)`

And (ii) we need equivalent quantities of dinitrogen gas.....

`-=(1.4*g)/(28.01*g*mol^-1)=0.050*mol` with respect to `N_2`.

Given the equation I can make AT MOST `0.100*mol` with respect to ammonia........Agreed?

Since an ideal gas has a molar volume at STP of `22.4*L*mol^-1` (or whatever your syllabus says), we gots a volume of....

`22.4*L*mol^-1xx0.05*mol~=1*L`