Question

Question #0cda4

Answer 1

`3(n+3)-2n`
simplified version :
`n+9`

Explanation:

let us start by breaking up the given
expression of :
difference..A of 3* the number ..B after it was increased by 3..C.

We see that the number was first increased by 3
`rarr (n)+3`

Then the result was multiplied by 3 (3 times):
`rarr 3((n)+3)`

Then eventually the difference is wanted to be found between the result and twice the number:
`rarr 3((n)+3)-2(n)`

Now simplifying the final expression:
`rarr 3((n)+3)-2(n)=3(n)+9-2n=3n-2n+9=n+9`