Question

Question #210d9

Answer 1

See below.

Explanation:

Here it is a conceptual approach.

Here, We get `h=1/2g t^2` where `h` is the height of the house from the ground level, `g` is the gravitational acceleration and `t` is the time taken.

Hence ,we get `t=sqrt((2h)/g`
Putting the given value we get `t` is `sqrt((2xx60)/10)=3.46s`

Now we have to determine the distance covered in `X` axis.
As we have get the initial velocity of the egg(u) is `6.5m//s` and time taken to touch the ground is `3.46s`,hence the distance is
`(6.5xx3.46)m=22.52m`.
Here's the answer....
Enjoy physics...
Sorry for my mistake....