Applying the laws of exponents, how do we simplify #(16^(-1/2))^(-1/2)# ?
1 Answer
Sep 12, 2017
Explanation:
#"using the "color(blue)"laws of exponents"#
#•color(white)(x)(a^m)^n=a^(mn)#
#•color(white)(x)a^(m/n)=root(n)(a^m)#
#rArr(16^(-1/2))^(-1/2)=16^((1/2xx1/2))=16^(1/4)#
#rArr16^(1/4)=root(4)(16)=2#
