How do you graph #y+4=-5/2(x-3)#?

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Answer 1 · 2017-09-12T21:17:43

See a solution process below:

This is a linear equation. Therefore, first, solve for two points which solve the equation and plot these points:

First Point: For #x = 3#

#y + 4 = -5/2(3 - 3)#

#y + 4 = -5/2 * 0#

#y + 4 = 0#

#y + 4 - color(red)(4) = 0 - color(red)(4)#

#y + 0 = -4#

#y = -4# or #(0, -4)#

Second Point: For #x = 5#

#y + 4 = -5/2(5 - 3)#

#y + 4 = -5/2 * 2#

#y + 4 = -5#

#y + 4 - color(red)(4) = -5 - color(red)(4)#

#y + 0 = -9#

#y = -9# or #(5, -9)#

We can next graph the two points on the coordinate plane:

graph{((x-3)^2+(y+4)^2-0.239)((x-5)^2+(y+9)^2-0.239)=0 [-30, 30, -15, 15]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y+5/2x - 7/2)((x-3)^2+(y+4)^2-0.239)((x-5)^2+(y+9)^2-0.239)=0 [-30, 30, -15, 15]}