How do you evaluate $\frac { x ^ { 2} - 9} { x + 7} \div \frac { ( x + 3) } { 1}$ ?

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Answer 1 · 2017-09-13T07:21:18

$=1-10/(x+7)$

firstly, change using the rules of fractions change to a multiplication problem

$(x^2-9)/(x+7)-:(x+3)/1$

$=>(x^2-9)/(x+7)xx1/(x+3)$

secondly, factorise and cancel where possible

$(cancel((x+3))(x-3))/(x+7)xx1/cancel((x+3))$

$=(x-3)/(x+7)$

lastly change from an improper fraction

$=((x+7)-10)/(x+7)$

$=(x+7)/(x+7)-10/(x+7)$

$=1-10/(x+7)$

How do you evaluate \frac { x ^ { 2} - 9} { x + 7} \div \frac { ( x + 3) } { 1}\frac { x ^ { 2} - 9} { x + 7} \div \frac { ( x + 3) } { 1}?