How do you evaluate #x+13+x+12 = 19 #?

1 Answer
Sep 14, 2017

See a solution process below:

Explanation:

First, group and combine like terms on the left side of the equation:

#x + x + 13 + 12 = 19#

#1x + 1x + 13 + 12 = 19#

#(1 + 1)x + (13 + 12) = 19#

#2x + 25 = 19#

Next, subtract #color(red)(25)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#2x + 25 - color(red)(25) = 19 - color(red)(25)#

#2x + 0 = -6#

#2x = -6#

Now, divide each side of the equation by #color(red)(2)# to solve for #x# while keeping the equation balanced:

#(2x)/color(red)(2) = -6/color(red)(2)#

#(color(red)(cancel(color(black)(2)))x)/cancel(color(red)(2)) = -3#

#x = -3#