How do you evaluate #n^2 - n -3# for #n# = 4?

Question

2388 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-09-14T01:25:00

See a solution process below:

To evaluate the expression for #n#, substitute #color(red)(4)# for each occurrence of #color(red)(n)# and execute the operations:

#color(red)(n)^2 - color(red)(n) - 3# becomes:

#color(red)(4)^2 - color(red)(4) - 3 =>#

#16 - color(red)(4) - 3 =>#

#12 - 3 =>#

#9#

Answer 2 · 2017-09-14T01:25:04

9

#n^2-n-3#

for n=4:
#(4)^2-(4)-3#

#=16-4-3#

#=12-3#

#=9#