Question

Question #482a4

Answer 1

A 20-gon has exterior angles of `18^o`

Explanation:

As with any polygon the sum of the exterior angles must be `360^o`

Divide `360^o` by the number of angles of the polygon to determine the value of the exterior angle.

Triangle `(360^o)/3 = 120^o`

Square `(360^o)/4 = 90^o`

Pentagon `(360^o)/5 = 72^o`

So for a 20-gon divide `360^o` by `20`

20-gon `(360^o)/20 = 18^o`