How do you evaluate #4! \div \sqrt { 12} + \sqrt { \frac { 4} { 4} } \times 4.4#?

1 Answer
ErmWhat
Sep 15, 2017

#4sqrt(3)+4.4# or #11.33#.

Explanation:

First of all, #4!# is #4*3*2*1# or #24#.
Next, #sqrt(4/4) is sqrt(1)#, so that is just #1#.
#sqrt(12)# is #2sqrt(3)#.
After simplifying things, we get:
#24/(2sqrt(3)) + 1*4.4# = #12/sqrt(3) + 4.4#
For the fraction, multiply numerator and denominator by #sqrt(3)#.
#12sqrt(3)/(sqrt(3))^2+4.4# = #12sqrt(3)/3+4.4# = #4sqrt(3)+4.4#
And that's the answer!

The decimal answer to the nearest hundredth is #11.33#.

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