How do you evaluate #\frac { 2} { r + 4} = \frac { 4} { r }#?

1 Answer
Sep 15, 2017

See a solution process below:

Explanation:

Because both sides of the equation and single fractions we can "flip" the fractions giving:

#(r + 4)/2 = r/4#

Next, multiply each side of the equation by #color(red)(4)# to eliminate the fractions while keeping the equation balanced:

#color(red)(4) xx (r + 4)/2 = color(red)(4) xx r/4#

#cancel(color(red)(4))2 xx (r + 4)/color(red)(cancel(color(black)(2))) = cancel(color(red)(4)) xx r/color(red)(cancel(color(black)(4)))#

#2(r + 4) = r#

Then, expand the term on the left side of the equation by multiplying each term within the parenthesis by the term outside the parenthesis:

#(2 xx r) + (2 xx 4) = r#

#2r + 8 = r#

Now, subtract #color(red)(8)# and #color(blue)(r)# from each side of the equation to solve for #r# while keeping the equation balanced:

#-color(blue)(r) + 2r + 8 - color(red)(8) = -color(blue)(r) + r - color(red)(8)#

#-1color(blue)(r) + 2r + 0 = 0 - color(red)(8)#

#(-1 + 2)r = -8#

#1r = -8#

#r = -8#