Question

How many helium atoms are there in a helium blimp containing 535 kg of helium?

Answer 1

Approx.....`8xx10^28*"helium atoms"`

Explanation:

We work out (i) the molar quantity of helium gas....

`"Moles of helium"=(535*kgxx10^3*g*kg^-1)/(4.0*g*mol^-1)=133750*mol.`

And then (ii) we mulitply this molar quantity by Avogadro's number....`N_A=6.022xx10^23*mol^-1` to get the number of helium atoms.....

`6.022xx10^23*mol^-1xx133750*mol="an unfeasibly large number"`.