First, we will focus on #3/2(-4a-6)#.
We will use this: #x*y/z=(x*y)/z#
So it would be: #(-4a-6)*3/2=(3(-4a-6))/2#.
Now I will focus on the numerator which is #3(-4a-6)#.
We will focus on #(-4a-6)#. We will factor out the number #2#.
#-4a-6=2(2a+3)#. Now, put in the #3# back so the equation would be:
#-2color(blue)*color(blue)3(2a+3)# which is #-6(2a+3)#. Now put in the fraction back.
The equation would be: #-(6(2a+3))/2#.
Divide the numbers #6/2=3#.
Equation: #-3(2a+3)#
Now we will use: #x(y+z)=xy+xz# to distribute the brackets/parentheses. Imagine that #x=-3#, #y=2a# and #z=3#.
Using #x(y+z)=xy+xz#, the equation will be #-3(2a+3)=-3*2+ -3*3# which is the same as #-3*2a-3*3#.
Next, we multiply the numbers #3*2=6#.
The equation would be # -6a-3*3#.
Multiply the numbers #3*3=9#. to make it #-6a-9#. Add in the #-9# that you have to make the whole equation #-9-6a-9#.
Now we will simplify #-9-6a-9#. We will group like terms to #-6a-9-9#. Subtract the numbers #-9-9=-18#.
The final equation would be #-6a-18#.
