How did they get #6csc2x#?
The question was find the derivative of #y=(sin^2xtan^3x)/(x^2+1)^2# . I got #(2cotx+(3sec^2)/tanx-(4x)/(x^2+1))(sin^2xtan^3x)/(x^2+1)^2# as my solution. The correct answer is #(2cotx+6csc2x-(4x)/(x^2+1))(sin^2xtan^3x)/(x^2+1)^2#
The question was find the derivative of
1 Answer
Explanation:
Your Question is
and your answer is
there is a little bit of transformation
write
use Formula
we get
write
and you get the answer.