Question

Question #115c9

Answer 1

`1/3ln(abs(3x-6))+C`

Explanation:

Use u-substitution

u=3x-6
du = 3dx

du/3 = dx

Then integral turns into

`1/3int1/u du`

Take the integral
`1/3ln(abs(u))+C`

Then plug u back in

`1/3ln(abs(3x-6))+C`