Question

Question #321ec

Answer 1

1 mol of any compound has `6.02xx10^23` particles (Avogadro's number)

Explanation:

So `1.67mol` of `BBr_3` contains:
`1.67xx6.02*10^23=10.0*10^23=1.00*10^24` molecules of `BBr_3`
and, since one molecule of `BBr_3` contains just one atom of boron, that is also the answer to your question.

Note:
If the question had been about the bromine atoms, you would have had to multiply this by 3,