Question

How do you solve `\root[ 7] { 8x - 8} = \root [ 7] { 9x + 4}`?

Answer 1

`x = -12`

Explanation:

`root(7)(8x−8) = root(7)(9x+4)`
`(root(7)(8x−8))^7 = (root(7)(9x+4))^7`
`8x-8 = 9x+4`
`8x-8-9x =9x+4-9x`
`-1x -8 +8 = 4+8`
`-1x = 12`
`-1x/-1 = 12/-1`
`x = -12`