How do you simplify #\frac { 5x ^ { 3} \cdot 2x ^ { 2} } { 5x ^ { 4} }#?

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Answer 1 · 2017-09-17T02:42:13

Divide out common factors.

#2x#

#( 5x^3 xx 2 x^2)/ (5x^4) = (5 xx 2 xx x^5)/(5 x^4)#

# (5 xx 2 xx x^5) / (5x^4) = cancel5/cancel5 xx cancel(x^4)/cancel(x^4) xx 2 xx x #

Dividing out common factors leaves.

# 2 xx x #

Answer 2 · 2017-09-18T06:51:20

#2x#

#(cancel5x^3 * 2x^2)/(cancel5x^4)" "larr# cancel #(5/5=1)#

#=(2x^5)/(x^4)" "larr# to multiply, add the indices of like bases

#=2x" "larr# to divide, subtract the indices of like bases