Question

Question #b80a7

Answer 1

See explanation

Explanation:

Perhaps you mean solve for `y`?

If that's the case, we simply subtract `x` from both sides...

`cancel(x-x)+y=6-x`

`y=6-x`

That's all we can do in terms if determining what `y` is. We don't know what `x` so we can only express `y` as an expression and not a value. If we did know that value of `x` we could substitute the value for `x` and then solve for `y` to get some value.

For example, if `x=4` then

`y=6-(4)`

`y=2`