How do you solve #5< 4x + 3\leq 11#?

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Answer 1 · 2017-09-21T16:41:55

What you do to the center to make it become only x, you do to all 3.

Given: #5< 4x + 3 <= 11#

What you do to the center to make it become only x, you do to all 3.

Subtract 3:

#2 < 4x <= 8#

Divide by 4:

#1/2< x <= 2#

Solved

Answer 2 · 2017-09-21T17:35:51

#1/2< x <=2#

Subtract 3 from both sides:

#color(green)(2)<4x<=color(green)(8) #

Divide 4 from both sides:

#color(green)(2/4)< x <=color(green)(8/4)#

Simplify:

#color(green)(1/2)< x <=color(green)(2)#