Question

How do you solve `y= ( 1- 4) ^ { 2} + 1`?

Answer 1

`y = 10`

Explanation:

First, you evaluate `(1-4)`, which gives you `(3)`
This leaves you with `y = (-3)^2 + 1`
`(-3)^2 = 9` so this becomes `y = 9 + 1`
then simply add 9 and 1 so:
`y = 10`