Question #65fa6

1 Answer
Sep 22, 2017

#h^(-1)(x)=(x+5)/3#

Explanation:

You are asked to find the inverse function:

The first thing we do is to write #h(x)=3x-5# as #y=3x-5# and then switch the roles of #x# and #y# and solve for #y#.

So, #y=3x-5->x=3y-5#

Solving for #y# yields,

#xcolor(red)(+5)=3ycancel(-5color(red)(+5))#

#(x+5)/color(red)3=cancel3/cancelcolor(red)3y#

#(x+5)/color(red)3=y->h^(-1)(x)=(x+5)/3#