Question #d945a

1 Answer
Narad T.
Sep 22, 2017

See the proof below

Explanation:

We use

#cotx=cosx/sinx#

#cos^2x+sin^2x=1#

Therefore,

#LHS =cotx+(sinx)/(1+cosx)#

#=cosx/sinx+(sinx)/(1+cosx)#

#=(cosx(1+cosx)+sin^2x)/(sinx(1+cosx))#

#=(cosx+cos^2x+sin^2x)/(sinx(1+cosx))#

#=cancel(cosx+1)/(sinxcancel(1+cosx))#

#=1/sinx=cscx=RHS#

#QED#

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