How do you find the sum of #Sigma (3i-1)# from i=1 to 6? Calculus Introduction to Integration Sigma Notation 1 Answer Pankaj Solanki Sep 22, 2017 57 Explanation: #Sigma_1^6(3i-1)# -1 is repeated 6 times #Sigma_1^6(3i)-6# #=3(1+2+3+4+5+6)-6# #=3(21)-6# #=63-6=57# Answer link Related questions How does sigma notation work? How do you use sigma notation to represent the series #1/2+1/4+1/8+…#? Use summation notation to express the sum? What is sigma notation for an arithmetic series with first term #a# and common difference #d# ? How do you evaluate the sum represented by #sum_(n=1)^5n/(2n+1)# ? How do you evaluate the sum represented by #sum_(n=1)^(8)1/(n+1)# ? How do you evaluate the sum represented by #sum_(n=1)^(10)n^2# ? What is sigma notation for a geometric series with first term #a# and common ratio #r# ? What is the value of #1/n sum_{k=1}^n e^{k/n}# ? Question #07873 See all questions in Sigma Notation Impact of this question 6099 views around the world You can reuse this answer Creative Commons License