Question

Question #3b0fd

Answer 1

`1.53" mol NaOH"`

Explanation:

We set up the following expression:

`60"g" "NaOH"times(1"mol NaOH")/(M " NaOH")`

Where `M` is the molar mass of the `"NaOH"` in grams

The molar mass of `"Na"` is `22.98"g"`

The molar mass of `"O"` is `15.99"g"`

The molar mass of `"H"` is `1.01"g"`

So the sum of these molar masses is the molar mass of `"NaOH"` and that gives us: `39.98"g"`

Going back into our expression,

`60"g" "NaOH"times(1"mol NaOH")/(39.98g " NaOH")`

`60cancel("g" "NaOH")times(1"mol NaOH")/(39.98cancel(g " NaOH"))=(60*1"mol NaOH")/39.98=1.53" mol NaOH"`