Question

Question #166d8

Answer 1

`m=17`

Explanation:

The expression given by the problem is:

`(2m+1)+(2m+5)=74`

So we have to solve for `m`

First we identify and combine like terms:

`color(red)(2m)+color(blue)1+color(red)(2m)+color(blue)5=74`

`4m+6=74`

Then subtract `6` from both sides

`4mcancel(+6color(red)(-6))=74color(red)(-6)`

`4m=68`

Divide `4` from both sides

`cancel4/cancelcolor(red)4m=74/color(red)4`

`m=17`

So if we wanted to find what these two numbers were, we could substitute `17` for `m` back into `(2m+1)` and `(2m+5)` and evaluate. So...

`2(color(red)17)+1=35`

`2(color(red)17)+5=39`

And we know that our value for `m` is correct since the sum of `35` and `39` is `74`