How do you simplify #((2(-1)-1)^{2}-9)\div (x+1)#?

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Answer 1 · 2017-09-24T10:59:19

Answer is #0#.

#((2(-1)-1)^{2}-9)\div (x+1)#

Apply BODMAS rule and first simplify the innermost brackets:

=#((-2-1)^{2}-9)\div (x+1)#

=#((-3)^{2}-9)/ (x+1)#

=#((9)-9)/ (x+1)#

=# 0/(x+1)#

=#0#