The arithmetic sequence formula is:
#a_n = a_1 + (n – 1)d# Where:
#a_n# is the nth term in the sequence
#a_1# is the first term in the sequence
#n# is the term you are solving for
#d# is the common difference for any pair of consecutive numbers in the sequence.
First Term or #n = 1#:
This is given in the problem.
#a_1 = 5#
Second Term or #n = 2#:
Substitute #2# for #n# in the formula and substitute the values from the problem giving:
#a_2 = 5 + ((2 – 1) xx 6)#
#a_2 = 5 + (1 xx 6)#
#a_2 = 5 + 6#
#a_2 = 11#
Fifth Term or #n = 5#:
Substitute #5# for #n# in the formula and substitute the values from the problem giving:
#a_5 = 5 + ((5 – 1) xx 6)#
#a_5 = 5 + (4 xx 6)#
#a_2 = 5 + 24#
#a_2 = 29#
Using this same process you should be able to determiner the
Third Term or #n = 3#: and Fourth Term or #n = 4#:
