How do you solve #2(x-4)+8=\frac{1}{2}(6x+20)#?

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Answer 1 · 2017-09-24T20:57:32

x = -10

On the left: multiply through by 2 for the term in parens.
On the right: multiply through by 1/2. This gives:

#2x - 8 + 8 = 3x + 10#

# 2x = 3x + 10#

...Couple of ways you can go from here. I choose to subtract 3x from each side:

#-x = 10#

Multiply by -1 on each side:

#x = -10#

Check your work when you can. Plug -10 into the original equation. Does it check out?

#2((-10) - 4) + 8 = 1/2 (6(-10) + 20)#

#-28 + 8 = -40/2#

#-20 = -20#

so, it checks out. If your solved value for x was wrong, the equation immediately above would be wrong. #-20 = 25#, or some such.

GOOD LUCK!