Question

How do you factor `4n^{2}-15n-4`?

Answer 1

(4n+1)(n-4)

Explanation:

`4n^2-15n-4`
`4n^2-16n+1n-4`
`4n(n-4)+1(n-4)`
`(4n+1)(n-4)`

Thus the factors are (4n+1)(n-4)