What is the possible answer for #sqrt2x(sqrt8x-sqrt32)#? How to simplify the answer too?
#sqrt2x(sqrt8x-sqrt32)#
2 Answers
Explanation:
Now that's out of the way, using the same logic:
How did they get
Pull it apart and you get:
Same thing here:
After picking apart everything we get:
Simplifying:
Given
Let us take
#x (sqrt2xxsqrt8x - sqrt2xxsqrt(32))#
#=>x (sqrt(8xx2)x - sqrt(32xx2))#
#=>x (sqrt(16)x - sqrt(64))#
#=>x (4x - 8)#
Taking common factor
#4x (x - 2)#