How do you solve #|- 2d | \leq 12#?

1 Answer
Sep 26, 2017

See a solution process below:

Explanation:

The absolute value function takes any term and transforms it to its non-negative form. Therefore, we must solve the term within the absolute value function for both its negative and positive equivalent.

#-12 <= -2d <= 12#

Divide each segment of the system of inequalities by #color(blue)(-2)# to solve for #d# while keeping the system balanced. However, because we are multiplying or dividing inequalities by a negative number we must reverse the inequality operators:

#(-12)/color(blue)(-2) color(red)(>=) (-2d)/color(blue)(-2) color(red)(>=) 12/color(blue)(-2)#

#6 color(red)(>=) (color(blue)(cancel(color(black)(-2)))d)/cancel(color(blue)(-2)) color(red)(>=) -6#

#6 color(red)(>=) d color(red)(>=) -6#

Or

#d >= -6# and #d <= 6#

Or. in interval notation:

#[-6, 6]#