How do you solve #5t - 5= 37#?

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Answer 1 · 2017-09-26T12:40:33

See a solution process below:

First, add #color(red)(5)# to each side of the equation to isolate the #t# term while keeping the equation balanced:

#5t - 5 + color(red)(5) = 37 + color(red)(5)#

#5t - 0 = 42#

#5t = 42#

Now, divide each side of the equation by #color(red)(5)# to solve for #t# while keeping the equation balanced:

#(5t)/color(red)(5) = 42/color(red)(5)#

#(color(red)(cancel(color(black)(5)))t)/cancel(color(red)(5)) = 42/5#

#t = 42/5# or #8.4#