Question

What mass of `"ferric oxide"` would result from oxidation of a `58.7*g` iron metal. What mass of dioxygen is required?

Answer 1

Approx....`81*g`.....

Explanation:

`Fe_2O_3` has a molar mass of `159.69*g*mol^-1`..

We work from a molar quantity with respect to iron of `(58.7*g)/(55.8*g*mol^-1)=1.05*mol`, and thus with respect to oxygen, there are is `1.05*molxx3/2xx16*g*mol^-1=25.25*g` mass.

And so we just sum the masses, i.e. `55.8*g+25.25*g=??*g`