How do you solve # 6( s - 8) \leq - 18#?

1 Answer
Taha Z.
Sep 29, 2017

#s>=5#

Explanation:

#6(s-8)<=-18#

Let us start by dividing both sides of the inequality by 6:
#(cancel6(s-8))/cancel6<=-18/6#

Since 18=6*3 then:
#s-8<=-(cancel6*3)/cancel6#
#s-8<=-3#

Adding 8 to both sides to isolate the unknown #s# on the left side of the inequality:

#scancel(-8)cancel(+8)<=-3+8#

#rarr s>=5#

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