How do you solve #5x + 4 = 3x +6#?

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Answer 1 · 2017-09-29T11:26:27

See a solution process below:

First subtract #color(red)(4)# and #color(blue)(3x)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#-color(blue)(3x) + 5x + 4 - color(red)(4) = -color(blue)(3x) + 3x + 6 - color(red)(4)#

#(-color(blue)(3) + 5)x + 0 = 0 + 2#

#2x = 2#

Now, divide each side of the equation by #color(red)(2)# to solve for #x# while keeping the equation balanced:

#(2x)/color(red)(2) = 2/color(red)(2)#

#(color(red)(cancel(color(black)(2)))x)/cancel(color(red)(2)) = 1#

#x = 1#