Question #f7924

2 Answers
Sep 29, 2017

They react and form copper iodide(I) (CuI) and pottasium triodide(KI3).
Thank you for Gaya3's post.

Explanation:

I thought that reaction with copper sulfate(CuSO4) and potassium iodide(KI) does'nt happen for two reasons, but it was wrong.

This is what I have written:


(1) Potassium cation (K+) is very stable. K is one of alkali metals, which lies in the group 1 in the periodic table. In general,
alkali metal cations form no precipitation with any anions.

(2) Iodine anion (I) is also very stable. I is one of halogens,
in the group 17 in the periodic table. Halogen anions don't
precipitate expect with Ag+ and Pb2+.


What I did not notice was the fact that I has strong reducibility. Please see Gaya3's post for the chemical equation.

Sep 29, 2017

Yes!

Explanation:

Equation:

CuSO4+KICuI+K2SO4+KI3

After Balancing,

2CuSO4+5KI2CuI+2K2SO4+KI3

Watch it happen here