In the quadratic equation x^2+4ex=3f, e and f are constants. What are the solutions for x?

1 Answer
Sep 30, 2017

=-2e+-sqrt(4e^2+3f)

Explanation:

x^2+4ex=3f

=x^2+4ex-3f=0

Using the Quadratic Formula:

=(-4e+-sqrt((4e)^2-4*1*(-3f)))/2

=(-4e+-sqrt(16e^2+12f))/2

=(-4e+-2sqrt(4e^2+3f))/2

=-2e+-sqrt(4e^2+3f)