What is the hang time of a person who can jump a vertical distance of 0.6 m?

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Answer 1 · 2017-09-30T10:07:23

0.3499 seconds

The person jumps a height of 0.6 m .

Remember the kinematic equation ,

#S=ut+1/2at^2#

where ,

S is the displacement of the body (in this case it is height from which the person jumps )

u is the initially velocity . Here it is zero because the person jumps freely under the action of gravity and initially he is at rest .

a is the acceleration of the person .

t is the time taken to reach the distance . (Hang time)

Now substitute the values and find the value of hang time .

#0.6=0xxt+1/2g*t^2# .

g is the acceleration of the person . It is the acceleration due to gravity whose value is #9.8 ms^-2#.

#0.6=1/2xx9.8xxt^2#

#(0.6xx2)/9.8=t^2#

#t=sqrt(1.2/9.8)#

#t=0.3499 s#